A) butanol
B) aldol
C) ketol
D) acetal
Correct Answer: B
Solution :
\[\underset{acetic\,acid}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{LiAl{{H}_{4}}}\underset{(X)}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[300{}^\circ C]{Cu}\] \[C{{H}_{3}}CHO\xrightarrow{\begin{smallmatrix} Dil.\,NaOH \\ (aldol\,\,condensation) \end{smallmatrix}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} OH \\ (Z)\,aldol \end{smallmatrix}}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO\]You need to login to perform this action.
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