A) \[\frac{16}{9R}\]
B) \[\frac{16}{7R}\]
C) \[\frac{16}{5R}\]
D) \[\frac{16}{3R}\]
Correct Answer: D
Solution :
Wavelength of the emitted radiations \[\frac{1}{\lambda }=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] \[=R\left[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(4)}^{2}}} \right]\] \[=R\left[ \frac{1}{4}-\frac{1}{16} \right]\] or \[\lambda =\frac{16}{3R}\]
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