A) \[{{d}^{-2}}\]
B) \[{{d}^{2}}\]
C) \[{{d}^{-1}}\]
D) \[d\]
Correct Answer: A
Solution :
Mean free path, \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\]\[\lambda \propto {{d}^{-2}}\](where d is the molecular diameter)
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