CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    The compound in which underlined carbon uses only its\[s{{p}^{3}}\]hybrid orbitals for bond formation is

    A)  \[C{{H}_{3}}COOH\]                      

    B)  \[C{{H}_{3}}CON{{H}_{2}}\]

    C)  \[C{{H}_{3}}C{{H}_{2}}OH\]       

    D)  \[C{{H}_{3}}CH=C{{H}_{2}}\]

    Correct Answer: C

    Solution :

                    \[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-OH}}\,\]                   \[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-N{{H}_{2}}}}\,\] \[C{{H}_{3}}-\underset{H}{\overset{H}{\mathop{\underset{|\,s{{p}^{3}}}{\overset{|}{\mathop{C}}}\,}}}\,-OH\,s{{p}^{3}}\]               \[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{H}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\]


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