A) zero
B) one
C) two
D) four
Correct Answer: C
Solution :
\[{{O}_{2}}=8+8=16\]\[=\sigma \,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\]\[\pi 2p_{y}^{2},\pi 2p_{x}^{2},\overset{*}{\mathop{\pi }}\,2p_{y}^{1}\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\] \[\therefore \]Number of unpaired electrons = 2
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