A) \[6.29g\text{/}c{{m}^{3}}\]
B) \[2.23\text{ }g\text{/}c{{m}^{3}}\]
C) \[4.45g\text{/}c{{m}^{3}}\]
D) \[8.92\text{ }g\text{/}c{{m}^{3}}\]
Correct Answer: B
Solution :
Density of copper \[=\frac{Z\times M}{{{a}^{3}}\times {{N}_{0}}\times {{10}^{-30}}}g\,c{{m}^{-3}}\] Here, \[a=362\,pm,\]\[{{N}_{0}}=6.09\times {{10}^{23}}\] \[Z=12\]in fcc, \[M=63.546\] Density \[=\frac{12\times 63.546}{{{(362)}^{3}}\times 6.09\times {{10}^{23}}\times {{10}^{-30}}}\] \[=2.23\,g\,c{{m}^{3}}\]
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