A) \[{{d}^{-2}}\]
B) \[{{d}^{2}}\]
C) \[{{d}^{-1}}\]
D) \[d\]
Correct Answer: A
Solution :
Mean free path, \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\]\[\lambda \propto {{d}^{-2}}\](where d is the molecular diameter)You need to login to perform this action.
You will be redirected in
3 sec