A) 7
B) 10
C) 12
D) 18
Correct Answer: A
Solution :
For maximum intensity on the screen \[d\,\sin \theta =n\lambda \] or \[\sin \theta =\frac{n\lambda }{d}=\frac{n\,(2000)}{7000}=\frac{n}{3.5}\] Since the maximum value of \[\sin \theta =1\] \[\therefore \] n = 0, 1, 2 and 3 only So, only seven maximas can be obtained on both sides of the screen.You need to login to perform this action.
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