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CMC Medical CMC-Medical Ludhiana Solved Paper-2013

  • question_answer
    A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J. Then its internal energy

    A)  increases by 600 J

    B)  decreases by 800 J

    C)  increases by 800 J

    D)  decreases by 50 J

    Correct Answer: C

    Solution :

                    \[dQ=+\,200\,cal\] \[=200\times 4.2=840\,J\] \[dW=+\,40\,J\] From the first law of thermodynamics \[dQ=dU+dW\] \[dU=dQ-dW\]       \[=840-40=800\,J\] So, the internal energy of the .system increased by 800 J.


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