A) \[\frac{1}{9}m\]
B) \[\frac{1}{10}m\]
C) \[\frac{1}{11}m\]
D) \[\frac{10}{11}m\]
Correct Answer: C
Solution :
According to question, \[\frac{G\times 100}{{{x}^{2}}}=\frac{a\times 10,000}{(1-{{x}^{2}})}\] \[\frac{10}{x}=\frac{100}{(1-x)}\] \[x=\frac{1}{11}m\]You need to login to perform this action.
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