A) I and II
B) II and IV
C) III and IV
D) I and IV
Correct Answer: A
Solution :
\[S{{O}_{2}}\] can be oxidised to\[S{{O}_{3}}\]. \[Mn{{O}_{2}}\]can be oxidised to either \[MnO_{4}^{2-}\] or \[MnO_{4}^{-}\]. In\[A{{l}_{2}}{{O}_{3}}\] and \[Cr{{O}_{3}},\] \[Al\] and \[Cr\]are already in their highest oxidation states. So, cant be oxidized further.You need to login to perform this action.
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