A) \[B{{i}_{2}}{{O}_{5}}\]
B) \[Bi{{F}_{5}}\]
C) \[BiC{{l}_{5}}\]
D) \[B{{i}_{2}}{{S}_{5}}\]
Correct Answer: B
Solution :
Fluorine being the strongest oxidising agent, oxidises Bi to its highest oxidation state of +5 in\[Bi{{F}_{5}}.\]You need to login to perform this action.
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