A) \[2\pi \,N\text{-}m\]
B) \[0.4\pi \,N\text{-}m\]
C) \[\frac{2}{\pi }\,N\text{-}m\]
D) \[4\pi \,N\text{-}m\]
Correct Answer: B
Solution :
Angular acceleration \[\alpha =\frac{2\pi n}{t}\] \[=\frac{2\pi \times \frac{240}{60}}{20}\] \[=\frac{2\pi \times 4}{20}\] \[\alpha =\frac{2\pi }{5}\] Torque, \[\tau =\mathbf{/}\alpha \] \[\tau =M{{R}^{2}}\alpha \] \[=25\times (0.04)\times \frac{2\pi }{5}\] \[=0.4\pi \,N\text{-}m\]You need to login to perform this action.
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