A) \[\frac{2v\,\sin \theta }{g\,(\cos \theta )}\]
B) \[\frac{v\,\cos \theta }{(\sin \theta )g}\]
C) \[\frac{2v}{(\cot \theta -1)}\]
D) \[\frac{1}{3}vg\,\tan \theta \]
Correct Answer: A
Solution :
Consider the diagram For the motion of particle along X-axis \[AP=(v\,\cos \theta )t+\frac{1}{2}(g\sin \theta ){{t}^{2}}\] For the motion of particle along Y-axis displacement, \[0=-\,vt\,\sin \theta +\frac{1}{2}g{{t}^{2}}\cos \theta \] This gives, \[t=0,\,\frac{2v\,\sin \theta }{g\,\cos \theta }\] Clearly, time corresponding to point P is\[2v\sin \theta /g\cos \theta \]You need to login to perform this action.
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