A) \[2.1\times {{10}^{-8}}m\]
B) \[1.5\times {{10}^{-9}}m\]
C) \[3.7\times {{10}^{-7}}m\]
D) \[0.8\times {{10}^{-10}}m\]
Correct Answer: B
Solution :
Given, \[A=4\times {{10}^{-4}}{{m}^{2}}\] thickness, \[t=0.5\times {{10}^{-2}}\,m\] force, \[F=10\text{ }N\] Now \[E=\frac{F}{A\theta }\] Here, E = modulus of rigidity \[\Rightarrow \] \[\theta =\frac{F}{AE}=\frac{10}{4\times {{10}^{-4}}\times 84\times {{10}^{10}}}\] Now, lateral displacement\[=\theta t\] \[=0.297\times {{10}^{-6}}\times 0.5\times {{10}^{-2}}\] \[=1.5\times {{10}^{-9}}m\]You need to login to perform this action.
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