A) \[2.2\times {{10}^{-10}}m\]
B) \[3.7\times {{10}^{-9}}m\]
C) \[1.7\times {{10}^{-11}}m\]
D) \[1.9\times {{10}^{-10}}m\]
Correct Answer: A
Solution :
The pressure amplitude is \[{{p}_{0}}=\frac{1.0\times {{10}^{-3}}}{2}=0.5\times {{10}^{-3}}N{{m}^{-2}}\] Now, displacement amplitude. So is given by \[{{p}_{0}}=BK{{S}_{0}}\] \[\Rightarrow \] \[{{S}_{0}}=\frac{{{p}_{0}}}{BK}=\frac{{{p}_{0}}\lambda }{2\pi B}\] \[=\frac{0.5\times {{10}^{-3}}\times 40\times {{10}^{-2}}}{2\times 3.14\times 14\times {{10}^{5}}}\] \[=2.2\times {{10}^{-10}}m\]You need to login to perform this action.
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