A) 2-butene
B) 2-butyne
C) Chlorobenzene
D) 3-methyl-1-butyne
E) 1, 3-butadiene
Correct Answer: D
Solution :
\[{{C}_{2}}{{H}_{2}}\] and all 1-alkynes give white precipitate with ammoniacal silver nitrate, therefore 3-methyl-1-butyne will give a white precipitate with ammoniacal silver nitrate. \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-C\equiv CH\xrightarrow[AgN{{O}_{3}}]{N{{H}_{4}}OH}\] \[\underset{\text{white}\,\text{ppt}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-C\equiv CAg\downarrow }}\,\]
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