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CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    A wire of length 50 cm moves with a velocity of 300 m/min, perpendicular to a magnetic field. If the emf induced in the wire is 2 V, the magnitude of the field in tesia is

    A)  2                                            

    B)  5

    C)  0.4                                        

    D)  2.5

    E)  0.8

    Correct Answer: C

    Solution :

                    When a wire of length\[l\]moves with a velocity \[v\] perpendicular to a magnetic field B, an induced emf is produced in the wire, given by \[e=Blv\] Given\[l=50\,cm=0.5\,m,\] \[v=300\,m\text{/}min\]    \[=\frac{300}{60}=5\,m\text{/}s\] \[e=2V\] Magnetic field, \[B=\frac{e}{lv}\]    \[=\frac{2}{0.5\times 5}=0.8\,T\]


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