A) \[13.5\,{}^\circ C\]
B) \[150{}^\circ C\]
C) \[75\,K\]
D) \[13.5\,K\]
E) \[-123{}^\circ C\]
Correct Answer: E
Solution :
Kinetic energy of a gas molecule \[E=\frac{3}{2}kT\]where\[k\]is Boltzmanns constant. \[\therefore \] \[E\propto T\] or \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] or \[\frac{E}{(E\text{/}2)}=\frac{300}{{{T}_{2}}}\] or \[{{T}_{2}}=150\,K\] \[{{T}_{2}}=150\,-273\] \[=-\,123{}^\circ C\]
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