CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    A body of mass 20 g connected to spring of constant k executes simple harmonic motion with a frequency of\[\left( \frac{5}{\pi } \right)Hz.\]. The value of spring constant is

    A)  \[4\,N\text{-}{{m}^{-1}}\]                          

    B)  \[3\,N\text{-}{{m}^{-1}}\]

    C)  \[2\,N\text{-}{{m}^{-1}}\]                          

    D)  \[5\,N\text{-}{{m}^{-1}}\]

    E)  \[2.5\,N\text{-}{{m}^{-1}}\]

    Correct Answer: C

    Solution :

                    Mass (m) = 20 g = 0.02 kg Frequency\[(f)=\frac{5}{\pi }Hz.\] Time period of a loaded spring \[T=2\pi \sqrt{\frac{m}{k}}\] Frequency \[(f)=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] \[\frac{5}{\pi }=\frac{1}{2\pi }\sqrt{\frac{k}{0.02}}\] or            \[10=\sqrt{\frac{k}{0.02}}\] or            \[100=\frac{k}{0.02}\] \[\therefore \]  \[k=2\,N\text{-}{{m}^{-1}}\]


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