A) \[3\times {{10}^{-12}}N\]
B) \[8\times {{10}^{-10}}N\]
C) \[8\times {{10}^{-12}}N\]
D) \[2\times {{10}^{-10}}N\]
E) \[3\times {{10}^{-10}}N\]
Correct Answer: C
Solution :
Energy of proton = 2 MeV \[=2\times 1.6\times {{10}^{-19}}\times {{10}^{6}}J\] \[=3.2\times {{10}^{-13}}J\] Magnetic field = 2.5 T Mass of proton (m) \[=1.6\times {{10}^{-27}}kg\] Energy of proton, \[E=\frac{1}{2}m{{v}^{2}}\] \[\therefore \] \[v=\sqrt{\frac{2E}{m}}\] ?(i) Magnetic force on proton \[F=B\,q\,v\,\sin 90{}^\circ \] \[=B\,q\,v\] Substituting the value of v from Eq. (i) \[F=Bq\sqrt{\frac{2E}{m}}\] \[=2.5\times 1.6\times {{10}^{-19}}\sqrt{\frac{2\times 3.2\times {{10}^{-13}}}{1.6\times {{10}^{-27}}}}\] \[=8\times {{10}^{-12}}N\]
You need to login to perform this action.
You will be redirected in
3 sec
