A) \[2.5\times {{10}^{10}}\]
B) \[2.5\times {{10}^{11}}\]
C) \[2.5\times {{10}^{12}}\]
D) \[2.5\times {{10}^{9}}\]
E) \[2.5\times {{10}^{13}}\]
Correct Answer: A
Solution :
Energy of a photon \[E=\frac{hc}{\lambda }\] Given \[\lambda =5000\overset{\text{o}}{\mathop{\text{A}}}\,=5\times {{10}^{-7}}m\] \[\therefore \] \[E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{5\times {{10}^{-7}}}\] \[=3.96\times {{10}^{-19}}J\] Energy received per second\[={{10}^{-8}}J\text{/}s\] \[\therefore \]Number of photons received per second \[=\frac{\text{Energy received per second}}{\text{Energy of one photon}}\] \[=\frac{{{10}^{-8}}}{3.96\times {{10}^{-19}}}=2.5\times {{10}^{10}}\]
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