A) 50
B) 5
C) 10
D) 25
E) 15
Correct Answer: B
Solution :
Mass of each bullet (m) \[=1\,g=0.001\,\,kg\] Velocity of bullet (v) \[=10\,\,m{{s}^{-1}}\] Applied force (F) \[=5g\text{-}wt\]. \[=\frac{5}{1000}\times 10N\] \[=0.05\,N\] Let n bullets are fired per second, then Force = rate of change of linear momentum ie, \[F=n\times mv\] \[\therefore \] Number of bullets fired per second \[n=\frac{F}{mv}\] \[=\frac{0.05}{0.001\times 10}\] \[=5\]You need to login to perform this action.
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