A) 1\[\Omega \]
B) 2\[\Omega \]
C) 4\[\Omega \]
D) 6\[\Omega \]
E) 8\[\Omega \]
Correct Answer: D
Solution :
Let a resistance r ohm be shunted with resistance S, so that the bridge is balanced. If S is the resultant resistance of S and r then In balanced position \[\frac{P}{Q}=\frac{R}{S}\] \[\frac{2}{2}=\frac{2}{S}\] \[\therefore \] \[S=2\Omega \] Now \[\frac{1}{S}=\frac{1}{S}+\frac{1}{r}\] or \[\frac{1}{r}=\frac{1}{S}-\frac{1}{S}\] \[=\frac{1}{2}-\frac{1}{3}=\frac{3-2}{6}\] \[\frac{1}{r}=\frac{1}{6}\] \[r=6\,\Omega \]You need to login to perform this action.
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