A) P only
B) R and S
C) R only
D) P and Q
E) P and R
Correct Answer: D
Solution :
Centre of mass \[{{C}_{1}}\] of the point masses placed at comers P and S from point P \[=\frac{1\times 0+2\times a}{1+2}=\frac{2a}{3}\] Therefore, distance of centre of mass \[{{C}_{1}}\] from point S \[=a-\frac{2a}{3}=\frac{a}{3}\] Similarly centre of mass \[{{C}_{2}}\]of point masses placed at comers Q and R, from point\[Q=\frac{2a}{3}\] Distance of centre of mass \[{{C}_{2}}\] from point R \[=a-\frac{2a}{3}=\frac{a}{3}\] Centre of mass of all four point masses is at the mid point of the line joining \[{{C}_{1}}\] and \[{{C}_{2}},\] which is farthest from points P and Q.You need to login to perform this action.
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