A) 10 mH
B) 15 mH
C) 25 mH
D) 20 mH
E) 5 mH
Correct Answer: E
Solution :
From Faradays law of electromagnetic induction \[e=-\frac{Mdi}{dt}\] \[\Rightarrow \] \[M=-\frac{e}{di\text{/}dt}\] Given, \[e=5\pi \]volt, \[i=10\,\sin \,(100\pi t)A,\] \[{{\left( \frac{di}{dt} \right)}_{\max }}=10\times 1000\,\pi \] \[\therefore \] \[M=-\frac{5\pi }{10\times 100\pi }\] \[=-5\times {{10}^{-3}}H=5\,mH\]You need to login to perform this action.
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