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CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    The bond dissociation energies of \[{{H}_{2}},\,C{{l}_{2}}\] and \[HCl\] are 104, 58 and 103 kcal\[\text{mo}{{\text{l}}^{-1}}\] respectively. The enthalpy of formation of \[HCl\]would be

    A)  \[-\,22\text{ kcal mo}{{\text{l}}^{-1}}\]                

    B)  \[-\,44\text{ kcal mo}{{\text{l}}^{-1}}\]

    C)  \[+\,44\text{ kcal mo}{{\text{l}}^{-1}}\]               

    D)  \[+\,22\text{ kcal mo}{{\text{l}}^{-1}}\]

    E)  \[-\,11\text{ kcal mo}{{\text{l}}^{-1}}\]

    Correct Answer: A

    Solution :

                    \[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl\] Enthalpy of formation of\[HCl\] \[=\frac{(104+58)-(2\times 103)}{2}\] \[=\frac{162-206}{2}=-\frac{44}{2}\] \[=-\,22\,\text{kcal}\,\text{mo}{{\text{l}}^{-1}}\]


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