A) 1 is a strong reducing agent
B) 2 is a d-block element
C) 3 has high electron affinity
D) 4 shows variable oxidation state
E) The compound formed between 1 and 3 is ionic
Correct Answer: B
Solution :
\[[Xe]\,\,4{{f}^{14}},5{{d}^{1}},6{{s}^{2}}\] is not a d-block element. It is lutetium and it is present in lanthanide series, so it is \[f\text{-}\]block element.You need to login to perform this action.
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