A) 2s
B) 2p
C) 3d
D) 4f
E) 5f
Correct Answer: A
Solution :
\[\because \]Angular momentum \[=\sqrt{l(l+1)}\frac{h}{2\pi }\] If angular momentum of an electron is zero then the value of \[l\] is also zero, therefore the electron may be present in s-orbital i.e. 2 s-orbitalYou need to login to perform this action.
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