CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    The resistance of N/10 solution is found to be \[2.5\times {{10}^{3}}\]ohm. The equivalent conductance of the solution is (cell constant = 1.25\[c{{m}^{-1}}\])

    A)  \[2.5\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}}\]

    B)  \[5.0\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}}\]

    C)  \[2.5\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}}\]

    D)  \[5.0\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}}\]

    E)  \[1.25\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}}\]

    Correct Answer: B

    Solution :

                    Resistance of N/10 solution\[=2.5\times {{10}^{3}}\Omega \] \[\kappa =\frac{1}{\text{resistance}}\times \text{cell}\,\text{constant}\] \[=\frac{1}{2.5\times {{10}^{3}}}\times 1.25\] \[=\frac{1.25\times {{10}^{-3}}}{2.5}=5\times {{10}^{-4}}\text{oh}{{\text{m}}^{-1}}\text{c}{{\text{m}}^{-1}}\] Equivalent conductance \[=\frac{\kappa \times 1000}{M}\] \[=\frac{5\times {{10}^{-4}}\times 1000}{1/10}\] \[=5\,\text{oh}{{\text{m}}^{-1}}\,\text{c}{{\text{m}}^{2}}\,\text{equ}{{\text{i}}^{-1}}\]


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