A) \[C{{H}_{4}}\]
B) \[N{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[SiC{{l}_{4}}\]
E) \[PC{{l}_{3}}\]
Correct Answer: C
Solution :
The hybridisation in \[{{C}_{2}}{{H}_{4}}\] molecule is \[s{{p}^{2}},\] hence it is planar in shape.
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