A) A is 4/6 times stronger than B
B) A is 10 times stronger than B
C) A is 6/4 times stronger than B
D) B is 10 times stronger than A
Correct Answer: B
Solution :
\[p{{K}_{a}}=-\log {{K}_{a}}\] \[\therefore \] \[{{(p{{K}_{a}})}_{A}}=-\log {{({{K}_{a}})}_{A}}\] \[{{({{K}_{a}})}_{A}}=\text{antilog}\,(-4)={{10}^{-4}}\] Similarly, \[{{({{K}_{a}})}_{B}}=\text{antilog}\,(-6)={{10}^{-6}}\] \[\frac{Strength\,of\,A}{Strength\,of\,B}=\sqrt{\frac{{{K}_{a}}}{{{K}_{b}}}}=\sqrt{\frac{{{10}^{-4}}}{{{10}^{-6}}}}=10\] \[\therefore \] Strength of A = 10 x strength of B.
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