A) \[CuCl\]
B) \[Cu{{F}_{2}}\]
C) \[A{{g}_{2}}S{{O}_{4}}\]
D) \[Mg{{F}_{2}}\]
Correct Answer: B
Solution :
In \[Cu{{F}_{2}},\] \[Cu\]is present as\[C{{u}^{2+}}\]. \[C{{u}^{2+}}=[Ar]\,3{{d}^{9}},4{{s}^{0}}\] Since, in it one unpaired electron is present, it is coloured.
You need to login to perform this action.
You will be redirected in
3 sec
