A) 9.6 V
B) 6.6 V
C) 4.8 V
D) 3.2 V
Correct Answer: D
Solution :
Potential difference across PQ ie, potential difference across the resistance of 20\[\Omega \] is \[V=i\times 20\]and \[i=\frac{48}{(100+100+80+20)}=0.16\,A\] \[\therefore \] \[V=0.16\times 20=3.2\,volt\]You need to login to perform this action.
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