A) \[S{{O}_{2}}\]and \[C{{l}_{2}}\]
B) \[CO\]and \[C{{l}_{2}}\]
C) \[N{{H}_{3}}\]and\[S{{O}_{2}}\]
D) \[{{H}_{2}}S\]and \[B{{r}_{2}}\]
Correct Answer: A
Solution :
The bleaching action of\[S{{O}_{2}}\]is due to reduction while the bleaching action of \[C{{l}_{2}}\]is due to oxidation.
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