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CMC Medical CMC-Medical VELLORE Solved Paper-2009

  • question_answer
    At ordinary temperature, the molecules of an ideal gas have only translational and rotational kinetic energies. At high tempera-tures they may also have vibrational energy. As a result of this at higher temperatures (\[{{C}_{V}}\]= molar heat capacity at constant volume)

    A)  \[{{C}_{V}}=\frac{3}{2}R\] for a monoatomic gas

    B)  \[{{C}_{V}}>\frac{3}{2}R\]for a monoatomic gas

    C)  \[{{C}_{V}}<\frac{5}{2}R\]for a diatomic gas

    D)  \[{{C}_{V}}=\frac{5}{2}R\]for a diatomic gas

    Correct Answer: A

    Solution :

                    At ordinary temperature, the vibrational kinetic energy of a monoatomic gas is zero. So,           \[{{C}_{V}}=\frac{3}{2}R\] The value is same for high temperature also. In case of diatomic gas \[{{C}_{V}}=\frac{5}{2}R\] (at low temperature) Also, \[{{C}_{V}}=\frac{5}{2}R\] (at high temperature due to vibrational kinetic energy)


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