A) 3-ethylhex-2-ene
B) 3-ethylpent-2-ene
C) 3-ethylpent-3-ene
D) 3-propylpent-2-ene
Correct Answer: A
Solution :
\[\begin{align} & {{H}_{3}}\overset{1}{\mathop{C}}\,-\overset{2}{\mathop{C}}\,H=\overset{3}{\mathop{C}}\,-C{{H}_{2}}-C{{H}_{3}} \\ & \underset{\begin{smallmatrix} \overset{6}{\mathop{C}}\,{{H}_{3}}\overset{5}{\mathop{C}}\,{{H}_{2}}\overset{4}{\mathop{C}}\,{{H}_{2}} \\ 3-ethylhex-2-ene \end{smallmatrix}}{\mathop{|}}\, \\ \end{align}\]You need to login to perform this action.
You will be redirected in
3 sec