CMC Medical CMC-Medical VELLORE Solved Paper-2009

  • question_answer
    sA lump of clay of mass 10 g travelling with a velocity of 10\[cm{{s}^{-1}}\]towards east collides head on with another lump of clay of mass 10 g travelling with velocity of 20\[cm{{s}^{-1}}\] towards west. If the two lumps coalesce collision, what is its velocity, if no external force acts on the system?

    A)  15 \[cm{{s}^{-1}}\] towards west            

    B)  15 \[cm{{s}^{-1}}\] towards east

    C)  5 \[cm{{s}^{-1}}\] towards west

    D)  5 \[cm{{s}^{-1}}\] towards east

    Correct Answer: C

    Solution :

                     Let velocity towards east be positive, then velocity towards west is negative. If v is the velocity of two lumps which are coalesced after collision, then from law of conservation of linear momentum \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\] \[10\times 20-10\times 10=20\times v\] \[\Rightarrow \]                               \[v=\frac{100}{20}=5\,cm{{s}^{-1}}\] Hence, 5\[cm{{s}^{-1}}\] towards west.


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