A) \[C{{H}_{4}}\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}CN\]
D) \[C{{H}_{3}}CO{{O}^{-}}NH_{4}^{+}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}COOH\xrightarrow{N{{H}_{3}}}\underset{X}{\mathop{C{{H}_{3}}COON{{H}_{4}}}}\,\xrightarrow[-{{H}_{2}}O]{\Delta }\] \[\underset{Y}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,\xrightarrow[-{{H}_{2}}O]{{{P}_{2}}{{O}_{5}}}\underset{(methyl\,cyanide)}{\mathop{\underset{Z}{\mathop{C{{H}_{3}}CN}}\,}}\,\]You need to login to perform this action.
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