A) \[C{{H}_{3}}OH\]
B) \[C{{H}_{3}}N{{H}_{2}}\]
C) \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}O{{H}^{-}}\]
D) \[C{{H}_{3}}\overset{+}{\mathop{N}}\,{{H}_{3}}C{{l}^{-}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}NH_{3}^{+}C{{l}^{-}}\]is a salt of methyl amine (weak base) and \[HCl\](strong acid). Hence, it is some what acidic in nature and liberates\[C{{O}_{2}}\]from\[NaHC{{O}_{3}}\].
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