CMC Medical CMC-Medical VELLORE Solved Paper-2009

  • question_answer
    In an organic compound, C = 68.5% and H = 4.91% . Which empirical formula is correct for it?

    A)  \[{{C}_{6}}{{H}_{10}}\]                 

    B)  \[{{C}_{7}}{{H}_{6}}{{O}_{2}}\]

    C)  \[{{C}_{5}}{{H}_{8}}O\]                

    D)  \[{{C}_{9}}{{H}_{3}}O\]

    Correct Answer: B

    Solution :

                   
    Element At. wt. Percent composition No. of moles Simple molar ratio
    C 12 68.5 \[\frac{68.5}{12}=5.708\] \[\frac{5.708}{1.67}=3.41\times 2\approx 7\]
    H 1 4.91 \[\frac{4.91}{1}=4.91\] \[\frac{4.91}{1.67}=2.95\times 2\approx 6\]
    O 16 \[(100-68.5+4.91)\]\[=26.59\] \[\frac{26.59}{16}=1.67\] \[\frac{1.67}{1.67}=1\times 2\approx 2\]
    Hence, the empirical formula of the compound is \[{{C}_{7}}{{H}_{6}}{{O}_{2}}\].


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