A) 1.12 L
B) 11.2 L
C) 21.1 L
D) 12.1 L
E) None of these
Correct Answer: B
Solution :
Molecular mass of nitrogen = 28 u 1 mole of nitrogen = 28 g = 22.4 L at STP, i.e., 28 g of nitrogen occupy 22.4 L at STP \[\therefore \]14 g of nitrogen will occupy\[=\frac{22.4}{2.8}\times 14\] = 11.2 L at STPYou need to login to perform this action.
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