A) 0.2
B) 0.1
C) 0.5
D) 0.4
E) None of these
Correct Answer: B
Solution :
As, \[v=n\lambda \] \[\therefore \] \[\lambda =\frac{v}{n}=\frac{300}{500}=\frac{3}{5}m\] Now, phase difference\[=\frac{2\pi }{\lambda }\times \]path difference \[\therefore \] \[60{}^\circ =\frac{2\pi }{\lambda }\times \]path difference or \[\frac{60{}^\circ \times \pi }{180{}^\circ }=\frac{2\pi \times 5}{3}\times \]path difference Path difference\[=\frac{3\times 60\times \pi }{2\pi \times 5\times 180}=0.1\]
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