A) 1.23
B) 1.0
C) 1.43
D) 0.75
E) None of these
Correct Answer: A
Solution :
\[\frac{N{{}_{\max }}}{{{N}_{\max }}}={{\left( \frac{v{{}_{c}}}{{{v}_{c}}} \right)}^{2}}\] \[={{\left( \frac{9+1}{9} \right)}^{2}}\] \[={{\left( \frac{10}{9} \right)}^{2}}=1.23\]You need to login to perform this action.
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