A) 4 cm
B) 8 cm
C) 25 cm
D) 12.5 cm
E) None of these
Correct Answer: C
Solution :
Comparing with \[y=a\,\text{cos}\left( \omega t+kx-\phi \right)\] We get, \[k=\frac{2\pi }{\lambda }=0.02\,\pi \] \[\Rightarrow \] \[\lambda =100\,km\] Also, it is given that phase difference between particles \[\Delta \phi =\frac{\pi }{2}.\] Hence, path difference between them \[\Delta x=\frac{\lambda }{2\pi }\times \Delta \phi \] \[=\frac{\lambda }{2\pi }\times \frac{\pi }{2}\] \[=\frac{\lambda }{4}=\frac{100}{4}\] = 25 cmYou need to login to perform this action.
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