A) 3.5 g
B) 2.8 g
C) 5.4 g
D) 6.2 g
E) None of these
Correct Answer: C
Solution :
From Faradays law, \[\frac{m}{E}=\]constant where m = mass of substance deposited E = chemical equivalent \[\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{{{E}_{2}}}{{{E}_{1}}}\] \[{{m}_{2}}=\frac{108}{32}\times 1.6\] \[=5.4\,g\]You need to login to perform this action.
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