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CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    0.01 M solution of\[KCl\]and\[BaC{{l}_{2}}\]are prepared in water. The freezing points of \[KCl\] is found to be\[-2{}^\circ C\]. What freezing point would you expect for \[BaC{{l}_{2}}\]solution assuming both \[KCl\]and \[BaC{{l}_{2}}\]to be completely ionised?

    A)  \[-3{}^\circ C\]                                

    B)  \[-2{}^\circ C\]

    C)  \[3{}^\circ C\]                                  

    D)  \[2{}^\circ C\]

    E)  None of these

    Correct Answer: A

    Solution :

                    \[i\]for \[KCl=2\]\[i\]for\[BaC{{l}_{2}}=3\] \[\frac{\Delta {{T}_{f}}(KCl)}{\Delta {{T}_{f}}(BaC{{l}_{2}})}=\frac{2}{3}\] \[\therefore \] \[\Delta {{T}_{f}}(BaC{{l}_{2}})=\frac{3}{2}\times \Delta {{T}_{f}}(KCl)\] \[=\frac{3}{2}\times 2=3{}^\circ \] \[\therefore \] Freezing point of\[KCl=-3{}^\circ C\]


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