A) \[{{I}^{-}}\]
B) \[CO_{3}^{2-}\]
C) \[{{S}^{2-}}\]
D) \[NO_{2}^{-}\]
E) \[C{{l}^{-}}\]
Correct Answer: B
Solution :
In \[CO_{3}^{2-},\]\[C\]is present in its highest oxidation state, i.e., +4 state, so its further oxidation is not possible, it only undergoes reduction. Acidified \[KMn{{O}_{4}}\] is a strong oxidising agent, but it cannot oxidise \[CO_{3}^{2-}\]. Hence, it will not be decolourised by\[CO_{3}^{2-}\].You need to login to perform this action.
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