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CMC Medical CMC-Medical VELLORE Solved Paper-2011

  • question_answer
    In an AC circuit, E = 220 sin 100\[\pi t\]. If the impedance is 110\[\Omega \] and phase angle\[\phi =60{}^\circ ,\] the power consumption is

    A)  440 W                                  

    B)  220 W

    C)  30 W                                    

    D)  55 W

    E)  1000 W

    Correct Answer: C

    Solution :

                                    \[{{E}_{0}}=220\,V\] \[\therefore \] \[{{E}_{rms}}=\frac{220}{\sqrt{2}}\] \[{{i}_{0}}=\frac{{{E}_{0}}}{Z}\] \[{{i}_{0}}=\frac{220}{110}=2A\] \[\Rightarrow \]               \[{{i}_{rms}}=\frac{2}{\sqrt{2}}\] Power \[={{E}_{rms}}\times {{i}_{rms}}\times \cos \phi \] \[=\frac{200}{\sqrt{2}}\times \frac{2}{\sqrt{2}}\times \cos 60{}^\circ \] \[=\frac{200}{\sqrt{2}}\times \frac{2}{\sqrt{2}}\times \cos 60{}^\circ \]


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