A) 10%
B) 20%
C) 15%
D) 5%
E) 25%
Correct Answer: B
Solution :
\[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] \[dH=\frac{2u{{\sin }^{2}}\theta }{2g}du\] \[\frac{dH}{H}=\frac{2du}{u}=2\times \frac{1}{10}\] \[\therefore \] increases in \[H=\frac{dH}{H}\times 100\] \[=\frac{2}{10}\times 100=20%\]You need to login to perform this action.
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